x/3 + y/3 = 7....1x/2 + y/3 = 7.......2. solve this equation by substitution method ​

Answers 1

Answer:

x=6 , y=21

Step-by-step explanation:

given :-

x/3 + y/3 = 7----------------(1)

x/2 + y/3 = 7---------------(2)

solving eq(1) -

x/3 + y/3 = 7

x+y/3 =7

x+y = 21

x=21-y------------------------(3)

solve eq(2) -

x/2+y/3 = 7

3x+2y/6 = 7

3x+2y = 42 ------------------(4)

substitute eq(3) in eq(4)-

3x+2y = 42

3(21-y)+2y = 42

63-3y+2y = 42

-y = 42-63

-y = -21

y = 21

substitute y in eq (3)

x = 21-y

x = 21-2

x = 0

(x,y) = (0,21)

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Find the correct ervous in the following mathemetical Statements: 5x+x=5x^2​

Ans.

x= 6/5

Step-by-step explanation:

5x + x = 5x^2

x (5+1) = 5x^2

6 = 5x

x= 6/5

Answer:

The roots of the equation are

x = 0 and x = 6 / 5.

Step-by-step-explanation:

The given quadratic equation is

5x + x = 5x².

We have to find the roots of the equation.

Now,

5x + x = 5x²

⇒ 6x = 5x²

⇒ 5x² - 6x = 0

Comparing with ax² + bx + c = 0, we get,

  • a = 5
  • b = - 6
  • c = 0

Now,

b² - 4ac = ( - 6 )² - 4 * 5 * 0

⇒ b² - 4ac = 36 - 0

⇒ b² - 4ac = 36

By quadratic formula,

x = [ - b ± √( b² - 4ac ) ] / 2a

⇒ x = [ - ( - 6 ) ± √36 ] / 2 * 5

⇒ x = ( 6 ± 6 ) / 10

⇒ x = 2 ( 3 ± 3 ) / 10

⇒ x = ( 3 ± 3 ) / 5

⇒ x = ( 3 + 3 ) / 5 OR x = ( 3 - 3 ) / 5

⇒ x = 6 / 5 OR x = 0 / 5

⇒ x = 6 / 5 OR x = 0

∴ The roots of the equation are

x = 0 and x = 6 / 5.

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