Find the value of: 243 ^1/5 x 64 ^1/2 x 1,000,000 ^1/3

Answers 1

Answer:

3^5)^1/5 ×(8^2)^1/2×(10^6)^1/3

3^1 ×8×10^2

=2400

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Step-by-step explanation:

Solution

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Correct option is A)

Given that:

t

1

+t

3

+t

5

=39

t

2

+t

4

+t

6

=51

To find:

t

10

=?

Solution:

Let a be the first term and d be the common difference.

t

1

+t

3

+t

5

=39

or, a+a+2d+a+4d=39

or, 3a+6d=39

or, a+2d=13 .............(i)

t

2

+t

4

+t

6

=51

or, a+d+a+3d+a+5d=51

or, 3a+9d=51

or, a+3d=17 .............(ii)

Subtracting eqn.(i) from eqn.(ii) we get,

d=4

Putting value d=4 in eqn.(i) we get,

a+2×4=13

or, a=13−8

or, a=5

Now, t

10

=a+9d

t

10

=5+9×4

t

10

=5+36

t

10

=41

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