The difference between the upper limit and lower limit of a class interval is called: a) Frequencyb) widthc) grouped datad) ungrouped data​

(x=4 , y=–4) , (x=6,y=–7)

This straight line can be written as in the intercept form as,

4

x

+

3

y

=1

From the intercept form of the given line, it can be concluded that the line intersects the co-ordinate axes at the points (4,0) and (0,3).

Now we get a triangle whose base is of length 4 units and length of perpendicular of length 3 units.

So, the area of the triangle will be,

⇒

2

1

×3×4

⇒6 sq. units

Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Consider the demand for four periods (in man hours) 300, 320, 400, 360. Production cost is Rs 10 and set up cost is Rs 1000. Inventory cost is Re 1 per unit/month. Backorder cost is Re 1/month? Find the production quantities that minimize total cost usingWagner Whitin algorithm? Solve it without using Backorder cost and comment on the total cost after including backorder cost comparatively

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Observe the table and answer the following questions:

Price of 'X' in Rs. Quantity demanded of 'X' in kgs Quantity supplied of 'X' in kgs Relation between Demand (DD) and Supply (SS)

50 100 500 DD < SS

40 200 400 DD < SS

30 300 300 DD = SS

20 400 200 DD > SS

10 500 100 DD > SS

When the quantity supplied is more than the quantity demanded of commodity 'X', there is ____________ pressure on price. (upward, downward)

Answer:

the least common multiple (lcm) is 10830456

Answer:

189 ka lcm 2x3x3=18 hi aur 728 ka lcm 2x2x2x2x11 hi.456ka lcm 2x2x