the sum of two integeris 47 if one of integer-24find the other​

Answer:

25° buddy

Explanation:

the 2 angles equal to each other are 65 each so 130°

180-130= 50

the asked angle = 50/2 = 25°

Answer:

Explanation:

∠1 + 65° = 90°  (normal=90°)

∠1 = 90°- 65° = 25°

∠1 = 25°

∠2 = 25° (∠1=∠2 because angle of incidence is = angle of reflection )

Answer:

here is your answer

Step-by-step explanation:

Solution

(a) Steps of construction:

1. Draw a circle with centre O and having radius 3 cm.

2. To make the three points A, B, and C in the circle, join A to the centre of the circle O.

3. If m∠BAC is to be 50

o

,m∠BOC should be 100

o

.

4. If m∠ABC is to be 60

o

,m∠AOC should be 120

o

.

5. If m∠ACB is to be 70

o

,m∠AOB should be 140

o

.

6. Join the points B and C such that m∠AOC=100

o

and m∠BOC=120

o

>

Thus, ΔABC is the required triangle.

(b) Steps of construction:

1. Extend OA and draw perpendicular to it through A.

2. Extend OB and draw perpendicular to it through B.

3. In the same way draw perpendicular to OC through C.

Let the points of intersection of these perpendicular be P, Q and R, so we get the required ΔPQR.

(c) In the quadrilateral PAOC,

m∠AOC=120

o

⇒m∠P=180

o

−120

o

=60

o

.... (opposite angles of a quadrilateral are suplementary)

In the same way, m∠Q=180

o

−140

o

=40

o

And, m∠R=180

o

−100

o

=80

o

(x=4 , y=–4) , (x=6,y=–7)

This straight line can be written as in the intercept form as,

4

x

+

3

y

=1

From the intercept form of the given line, it can be concluded that the line intersects the co-ordinate axes at the points (4,0) and (0,3).

Now we get a triangle whose base is of length 4 units and length of perpendicular of length 3 units.

So, the area of the triangle will be,

⇒

2

1

×3×4

⇒6 sq. units

Step-by-step explanation:

hope it helps you sweetu hey cuty i think you are bussy but i always love you

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