(vi) (x + y) (x² - xy + y²)​

Answer:

Parts of a lever

The distance from the applied force or effort force to the fulcrum is called the effort or input arm and the distance from the load to the fulcrum is called the load or output arm

Explanation:

Answer:

A lever is a simple machine made of a rigid beam and a fulcrum. The effort (input force) and load (output force) are applied to either end of the beam. The fulcrum is the point on which the beam pivots. When an effort is applied to one end of the lever, a load is applied at the other end of the lever.

Explanation:

hope this helped you please mark as BRAINLIESTS answer

Answer:

1.-d.

2.-e.

3.-b.

4.-c.

5.-a.

Answer:

1 will be with d

2 will be with e

3 will be with b

4 will be with c

5 will be with a

I hope this helps

Explanation:

Nothing to explain

Answer:

1008

Step-by-step explanation:

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2 | 16  

2 | 8

2 | 4

2 | 2

2 | 1

2 | 42

3 | 21

7 | 7   | 1

2 | 72

2 | 36

2 | 18

3 |  9

3 | 3

  | 1

16 = 2 x 2 x 2 x 2

42 = 2 x 3 x 7

72 = 2 x 2 x 2 x 3 x 3

HCF = 2

Step-by-step explanation:

Consider,

[tex]\qquad\sf \: {tan}^{2}A - {sin}^{2}A \\ \\ [/tex]

can be rewritten as

[tex]\qquad\sf \: = \: \dfrac{ {sin}^{2} A}{ {cos}^{2} A} - {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \:\left( \dfrac{1}{ {cos}^{2} A} - 1\right) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \:\left( {sec}^{2}A - 1\right) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \: ({tan}^{2}A ) {sin}^{2}A \\ \\ [/tex]

[tex]\qquad\sf \: = \: {tan}^{2}A \: {sin}^{2}A \\ \\ [/tex]

Hence,

[tex]\qquad\sf\implies \bf \: {tan}^{2}A - {sin}^{2}A = {tan}^{2}A \: {sin}^{2}A \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Formulae Used

[tex]\sf \:tanx \: = \: \dfrac{sinx}{cosx} \\ \\ [/tex]

[tex]\sf \:secx \: = \: \dfrac{1}{cosx} \\ \\ [/tex]

[tex]\sf \: {sec}^{2}x - {tan}^{2}x = 1 \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information

[tex]\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{{More \: Formulae}}}} \\ \\ \bigstar \: \bf{sinx = \dfrac{1}{cosecx} }\\ \\ \bigstar \: \bf{cosx = \dfrac{1}{secx} }\\ \\ \bigstar \: \bf{tanx = \dfrac{sinx}{cosx} = \dfrac{1}{cotx} }\\ \\ \bigstar \: \bf{cot x= \dfrac{cosx}{sinx} = \dfrac{1}{tanx} }\\ \\ \bigstar \: \bf{cosec x) = \dfrac{1}{sinx} }\\ \\ \bigstar \: \bf{secx = \dfrac{1}{cosx} }\\ \\ \bigstar \: \bf{ {sin}^{2}x + {cos}^{2}x = 1 } \\ \\ \bigstar \: \bf{ {sec}^{2}x - {tan}^{2}x = 1 }\\ \\ \bigstar \: \bf{ {cosec}^{2}x - {cot}^{2}x = 1 } \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]