Find the ratio of 3400m to 17km

Answer:

37583825643 is the correct answer of this question

Answer:

48696+375837,76947

=3.75838256e10

Step-by-step explanation:

here is your answer

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Answer:

4608 ko 12 se divide kar do answer aajae ga

Explanation:

There are 4608 books which were packed in 12 cartons

To find how many books in each carton:

Divide 4608 by 12 then we can find how many Books packed in each carton

So Answer is : 4608÷12 =384

Answer:

16%

Step-by-step explanation:

let the price of 1 apple is 1

so the price of 21 apple is 21

and cp = sp +loss

cp = 21 +4 =25

loss% = loss/cp ×100

4/25 × 100 = 16%

Answer:

[tex]\qquad\qquad\qquad\boxed{ \sf{ \: \bf \:Loss\% \: = \: 16 \: \% \: }} \\ \\ [/tex]

Step-by-step explanation:

Given that, By selling 21 apples, vendor losses the selling price of 4 apples.

Let assume that

[tex]\sf \:Selling \: Price \: of \: 1 \: apple \: = \: Rs \: x \\ \\ [/tex]

So,

[tex]\sf\implies \sf \:Selling \: Price \: of \: 21 \: apples \: = \: Rs \: 21x \\ \\ [/tex]

Now,

[tex] \sf \:Loss = Selling \: Price \: of \: 4 \: apples \: \\ \\ [/tex]

[tex]\sf\implies \sf \:Loss = Rs \: 4x \: \\ \\ [/tex]

We know,

Selling Price, Cost Price and Loss are connected by the symbol

[tex]\sf \:Cost \: Price \: = \: Selling \: Price \: + \: Loss \\ \\ [/tex]

On substituting the values, we get

[tex]\sf \:Cost \: Price \: = \: 21x \: + \: 4x \\ \\ [/tex]

[tex]\sf\implies \sf \:Cost \: Price \: = \: 25x \\ \\ [/tex]

Now, We know

Selling Price, Cost Price and Loss % are connected by the relationship

[tex]\sf \:Loss\% \: = \: \dfrac{Loss}{Cost \: Price} \times 100 \: \% \\ \\ [/tex]

[tex]\sf \:Loss\% \: = \: \dfrac{4x}{25x} \times 100 \: \% \\ \\ [/tex]

[tex]\sf \:Loss\% \: = \: \dfrac{4}{1} \times 4 \: \% \\ \\ [/tex]

[tex]\sf\implies \bf \:Loss\% \: = \: 16 \: \% \\ \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information

[tex]\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ {More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}[/tex]

Discriminant of the equation.

⇒ 4x² - 5x - 3 = 0.

As we know that,

D = discriminant Or b² - 4ac.

Using this formula in this equation, we get.

⇒ D = (-5)² - 4(4)(-3).

⇒ D = 25 + 48.

⇒ D = 73.

Discriminant of the equation : 4x² - 5x - 3 = 0 is 73.

Nature of the roots of quadratic expression.

(1) Roots are real and unequal, if b² - 4ac > 0.

(2) Roots are rational and different, if b² - 4ac is a perfect square.

(3) Roots are real and equal, if b² - 4ac = 0.

(4) If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answer:

D=73

Step-by-step explanation:

a=4

b=-5

c=-3

NOW

D=b^2-4(4)(-3)

=-5^2-4*(-12)

=25+48

D=73