Find n so that 2^11÷2^5.=2^−3×2^2n-1

  • matematika

    Subject:

    Math
  • Author:

    mitzi
  • Created:

    1 year ago

Answers 1

Answer:

2^11÷2^-5 = 2^-3×2^2n-1

2^-3 = 2^-3×2^2n-1

2^-3 = 2^-3+2n-1

-3 = -3+2n-1

-3 = -4+2n

2n = 1

n = 1/2

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