Piston of cross sectional area, A₁ = 2 cm²
Piston is pushed at speed, v₁ = 2 cm/s
Cross sectional area of tube, A₂ = 40 mm² = 40/10 = 0.4 cm²
Speed of fluid which is outgoing, v₂ = x cm/s [Let it be x]
We will apply the Equation of Continuity here.
Equation of Continuity =>
A₁v₁ = A₂v₂
2 * 2 = 0.4 * x
x = 4/0.4
x = 10 cm/s
The speed of fluid that is outgoing will be 10 cm/s
The equation of continuity tells us about the moving of some quantity from one place to another. It needs to conserve the mass of volume element like volume element coming in equal amount as that of going out in equal amount.
Hii