What percentage of numbers from1to 90 has a 1 or a 9 as one of the digits?
Answers 2
Answer:
Correct answer is 30%
Look
A) for 1
1,11,12,13,14,15,16,17,18,19 = = 10 digits
21,31,41,51,61,71,81=7 digits
B) for 9
9,19,29,39,49,59,69,79,89-9 digits
90=1 digit
Total 27 digits that's why
(27*100)/90-30%
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Author:
patchesjqj1
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Answer:
There are 29 digits from 1 to 90. So, we have 32.22% of digits having 1 or 9.
Step-by-step explanation:
Total numbers are 90.
From 1 to 10, we have 2 ones and 1 nine. So total we have 3 digits.
From 11 to 20, we have 10 ones and 1 nine. So total we have 11 digits.
From 21 to 30, we have 1 one and 1 nine. So total we have 2 digits.
From 31 to 40, we have 1 one and 1 nine. So total we have 2 digits.
From 41 to 50, we have 1 one and 1 nine. So total we have 2 digits.
From 51 to 60, we have 1 one and 1 nine. So total we have 2 digits.
From 61 to 70, we have 1 one and 1 nine. So total we have 2 digits.
From 71 to 80, we have 1 one and 1 nine. So total we have 2 digits.
From 81 to 90, we have 1 one and 2 nines. So total we have 3 digits.
So, the total numbers from 1 to 90 are 3+11+2+2+2+2+2+2+3=29
Percentage of numbers from 1 to 90 = [tex]\frac{29}{90} *100=32.22%[/tex]
For more questions on percentage, check the following link:
https://brainly.in/question/36354?referrer=searchResults
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