please solve this factorisation problem​

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Answers 1

Answer:

just subtract the numbers and then plus the variables

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The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when screw is turned through two rotations (i) What is the pitch of screw? 0-5 (ii) What is the least count of screw gauge? i) When the screw gauge is used to measure the diameter of wire the reading on sleeve is found to be 0.5 mm and reading on thimble is found 27 divisions. What is the diameter of wire in centimetres? ​
Answer

Given,

Given,Number of circular

Given,Number of circulardivision = 50 divisions

Given,Number of circulardivision = 50 divisionsLinear distance moved

Given,Number of circulardivision = 50 divisionsLinear distance movedin two complete rotation = 1 mm

Given,Number of circulardivision = 50 divisionsLinear distance movedin two complete rotation = 1 mmTherefore,

Given,Number of circulardivision = 50 divisionsLinear distance movedin two complete rotation = 1 mmTherefore,(i) Pitch of the screw gauge

Given,Number of circulardivision = 50 divisionsLinear distance movedin two complete rotation = 1 mmTherefore,(i) Pitch of the screw gaugepitch = 2/1 ×1mm

= 0.5 mm

= 0.5 mm(ii) Least count of the screw gauge

= 0.5 mm(ii) Least count of the screw gaugeLeast count = nnoofcirculardivpi

= 50 × 0.5

= 1 0 ×5×5

= 0.01 mm

Write two irrational numbers between 1÷5 and 1÷6

Step-by-step explanation:

√11 and √13 are the required numbers

Absolute potential energy is measured from:(a): Centre of Earth (b): Surface of Earth(c):None of these (d): Poles of Earth​

Answer:

Absolute potential energy is measured from center of earth.

Explanation:

In any measurement absolute measurement always starts from zero.

since the potential energy at the center of the earth is zero, we can measure absolute potential energy from center of the earth.

pls tell answer fast​
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