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Answer:
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Step-by-step explanation:


In Fig. 6.40, find the values of x, y and z

Solution:
In triangle ABD
Using the angle sum property
∠BAD + ∠BDA + ∠ABD = 180°
Substituting the values
60° + x + 60° = 180°
x + 120° = 180°
x = 180 - 120 = 60°
Using the exterior angle property
∠ADC = ∠BAD + ∠ABD
Substituting the values
y = 60 + 60 = 120°
In triangle ADC
Using the exterior angle property
∠ADB = ∠DAC + ∠DCA
x = 30° + z
Substituting the value of x
60° = 30° + z
z = 60° - 30°
z = 30°
Therefore, the values of x, y and z are 60°, 120° and 30°.
✦ Try This: In ∆PQR, if ∠P = ∠R, and exterior angle PQA = 150°, then find the angles of the triangle
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mitchell170
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