population of a city decreased by 10% at the end of the first year and increases by 10% at the end of the second year and again decreased by 10% at the end of the third year if the population of the city at the end of the third year is 4455 then what was the population of the city of the beginning of the first year ?

Answers 2

Answer:

Initial population = 76,000

Change in 1st year = 10% increased

Change in 2nd year = 20% decreased

Formula used:

Calculation:

Final population = 76,000 × (110/100) × (80/100)

⇒ Final population = 76,000 × (11/10) × (4/5)

⇒ Final population = 66,880

∴ The final population after 2 years is 66,880

Answer:

5000

Step-by-step explanation:

Let the initial Population be=a

So,Population at the end of 1st year =a×90/100=9a/10

Population at the end of 2nd year=9a/10×110/100=99a/100

Population at the end of 3rd year =99a/100×90/100=891a/1000

ATQ

891a/100=4455

891a =4455×100=445500

a=445500/891=5000