6. Find the H.C.F. of the terms of the expression (4x³y²z - 16xy²z² + 12x²y²z²).​

  • matematika

    Subject:

    Math

  • Author:

    hahn

  • Created:

    1 year ago

Answers 1

Answer:

good question...

Step-by-step explanation:

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please answer this question everyone​
question img
Ans = 20000₹ is left

Answer:

bsjshususushje

Explanation:

hjjjjjjjjjjj

The speed of the boat in still water is 30 km/h. A boat travels for three hours downstream and thenreturns the same distance upstream in five hours. Find the speed of the stream​

Step-by-step explanation:

Solution

Let the age of A, 5 years ago be x

Then the age of B , 5 years ago will be 3x

According to question

(3x+5+6)/(x+5+12)=7/4

(3x+11)/(x+17)=7/4

12x+44=7x+119

5x+119−44

5x=75

x=15

A's present age =15+5=20

B's present age=3×15+5=45+5=50

Required ratio =(20−3):(50+3)=17:53

Answer:

mark me as brainliest......

answer img
find the difference of sum of successor and predecessor of the first five natural numbers​

Answer:

2+3+4+5-4+3+2+1

14-10

4

Answer:

[tex]10[/tex]

Step-by-step explanation:

First 5 natural numbers are

[tex]1 \: 2 \: 3 \: 4 \: 5[/tex]

Sum of successor

1 -2

2-3

3-4

4-5

5-6

[tex]2 + 3 + 4 + 5 + 6 = 20[/tex]

Sum of predecessor

1-0

2-1

3-2

4-3

5-4

[tex]0 + 1 + 2 + 3 + 4 = 10[/tex]

difference of sum of successor and predecessor of the first five natural numbers are

[tex]20 - 10 = 10[/tex]

what is molarity of barium chloride solution prepared by disolving 3.5g of bacl2 in enough water to make 500ml of solution given that atomic mass of barium = 127u and cl= 35.5u.

Calcium carbonate and calcium chloride.

1 mol CaCO

3

1 mol CaCl

2

and

1 CaCl

2

1 mol CaCO

3

Hydrochloric acid and calcium chloride.

2 mol HCl

1 CaCl

2

and

1 mol CaCl

2

2 HCl

Calcium carbonate and hydrochloric acid.

1 mol CaCO

3

2 mol HCl

and

2 mol HCl

1 mol CaCO

3

Determine the moles of each reactant by dividing the given masses by their molar masses.

28.0

g CaCO

3

×

1

mol CaCO

3

100.1

g CaCO

3

=

0.280 mol CaCO

3

12.0

g HCl

×

1

mol HCl

36.5

g HCl

=

0.329 mol HCl

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