Subject:
MathAuthor:
irvinsteinCreated:
1 year agoAnswer:
Given :-Let,
[tex]\mapsto \bf Other\: Number =\: y\\[/tex]
Given :
According to the question by using the formula we get,
[tex]\small \implies \sf\boxed{\bold{Product\: Of\: Two\: Numbers =\: HCF \times LCM}}\\[/tex]
[tex]\implies \sf 865 \times y =\: 173 \times 6055\\[/tex]
[tex]\implies\sf 865y =\: 1047515\\[/tex]
[tex]\implies \sf y =\: \dfrac{1047515}{865}\\[/tex]
[tex]\implies \sf\bold{y =\: 1211}\\[/tex]
Hence, the required other number will be :
[tex]\dag[/tex] Other Number :-
[tex]\dashrightarrow \sf Other\: Number =\: y\\[/tex]
[tex]\dashrightarrow \sf\bold{\underline{Other\: Number =\: 1211}}\\[/tex]
[tex]\sf\boxed{\bold{\therefore\: The\: other\: number\: is\: 1211\: .}}\\[/tex]
Author:
julia44
Rate an answer:
4Answer:
The other will be 1211
Step-by-step explanation:
Given that,
HCF of two number = 173
Their LCM = 6055
One number = 865
To find,
The other number = a
Formula to be used,
Product of two numbers = HCF × LCM
Solution,
=> 865 × a = 173 × 6055
= 865a = 1047515
= a = 1047515 ÷ 865
= a = 1211
Therefore, the other number will be,
= a = 1211 ans.
Author:
warrenrhgl
Rate an answer:
8