In the given figure triangle ABC is an isosceles with AB=AC and OB=OC. Find the measure of AQB

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Answers 2

Answer:

angle AQB = 76°

Step-by-step explanation:

OB=OC

angle OBC = angle OCB and angle ABC = angle ACB, so angle ABQ and angle ACP are equal

angle POB = angle QOC (vertically opposite angles are equal)

Therefore, Triangle  POB ≅ QOC (ASA criteria of congruence)

angle OPB = 104° (180° - 76°)

angle OPB = angle OQC (as POB ≅ QOC)

angle OQC = 104°

angle AQB = 76° (180° - 104°)

Hope it will help

Angle AQB = 76

Refer to the attachment for detailed solution

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