find conjugate of [tex] \frac{(1 + i) {}^{2} }{1 - i {}^{3} } [/tex]​

Answers 2

Answer:

(1+2i)(2−i)

(3−2i)(2+3i)

=

2−i+4i+2

6+9i−4i+6

=

4+3i

12+5i

=

16−9

(12+5i)(4−3i)

=

5

48−36i+20i+15

=

5

63−16i

The conjugate is

5

63+16i

Answer:

3−2i)(2+3i)

=

2−i+4i+2

6+9i−4i+6

=

4+3i

12+5i

=

16−9

(12+5i)(4−3i)

=

5

48−36i+20i+15

=

5

63−16i

The conjugate is

5

63+16i

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