find the mean observation - 9 , 6, 8, 12, 16 Frequency - 2 , 5 , 4 , 6 , 3​

Answers 2

mean is calculated by calculating-

the sum of all the observations divided by the no. of observations

9+6+8+12+16 = 51÷5

therefore, the mean is 10.2

The answer is 10.2 . 10.2 is the answer

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Other related questions that may help you

who is the current representative in Bihar?​

Answer:

The current incumbent is Nitish Kumar who is having incumbency since 22 February 2015.

Please mark me as brainliest as it takes me a lot of time

Answer:

The current incumbent is Nitish Kumar who is having incumbency since 22 February 2015.

2. If A x B = {(2, 6), (1, 8), (2, 4), (1, 4), ( (2, 8)), then set A is equal to​

Given: [tex]A[/tex] × [tex]B[/tex] [tex]=((2, 6), (1, 8), (2, 4), (1, 4), ( (2, 8))[/tex]

To find: Set [tex]A[/tex]

Solution:

The set of [tex](a,b)[/tex], where [tex]a[/tex] is an element of set [tex]A[/tex] and [tex]b[/tex] is an element of set [tex]B[/tex], is known as [tex]A[/tex] × [tex]B[/tex].

[tex]A[/tex] has values of [tex]2, 1, 2, 1, 1, 2[/tex]

That is, [tex]1,2[/tex]  and [tex]A[/tex] have distinct values.

The values in the set [tex]A[/tex] are thus [tex]1[/tex] and [tex]2[/tex].

Therefore, the set [tex]A=(1,2)[/tex]

A 3000 kg rocket is fired. If the exhaust speed is ejected per second to supply the thrust needed, (a) to overcome the weight of the rocket, (b) to give the rocket an initial acceleration of 19.6m/ S^2

Answer:

Therefore, 176.4 kg gas must be ejected per second to supply the thrust needed for providing the rocket an acceleration of 19.6 m/s².

Answer:

Therefore, 176.4 kg gas must be ejected per second to supply the thrust needed for providing the rocket an acceleration of 19.6 m/s².

[tex].[/tex]

Explanation:

hope so it helps

Half yearly exam started on 23rd September 2021 and ended on 1st October 2021. How long did the exam continue.​

Answer:9

Step-by-step explanation:

It took 9 days for the exam to continue

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