THREE TIMES THE FIRST OF THE THREE CONSECUTIVE ODD INTEGERS IS 3 MORE THAN TWICE THE THIRD INTEGERS.FIND THE THIRD INTEGERS.PLZ HELP ME TO SOLVE THIS..!!❣️​

Answers 1

Answer:

Let the three consecutive odd integers be x, x+2, x+4

Three times the first of three consecutive odd integers is 3 more than twice the third.

∴ 3x=2(x+4)+3

∴ x=11

Hence, the third integer is 11+4=15.

Hence, option D is correct.

Step-by-step explanation:

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