Given
3, 6, 9, 12, 15, 18, .....
We can observe the above given series are in Arithmetic Progression.
First term of AP 'a' = 3
Common difference d = a2 - a1 = 6 - 3 = 3
We are asked to find Sum of 10 terms of the given series
So, Using sum of n terms of AP formula
Sn = n/2 [ 2a + ( n - 1 ) d ]
Sum of 10 terms S10 = 10/2 [ 2( 3 ) + ( 10 - 1 ) ( 3 ) ]
= 5 [ 6 + 9( 3 ) ]
= 5( 6 + 27 )
= 5( 33 )
= 165
Therefore the sum of 10 term of the given series is 165.
Author:
laci
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