give HCF (315, 657) =9 find LCM (315, 657)​

Answers 2

Answer:

22995

Step-by-step explanation:

lcmx hcf= product of two no.

lcm x9= 315x 657

lcm= 35 x 657= 22995

Answer:

Step-by-step explanation:

HCF(315,657)=9

HCF×LCM=product of the numbers

9×LCM = 315×657

LCM = 315×657/9

22995

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Other related questions that may help you

9. Evaluate : (1) 103 x 97 (3) 77 x 83 (2) 205 x 195 (4) 153 x 147​

Answer

1) 103×97= 9,991

2) 77×83= 6,391

3) 205×195= 39,975

4) 153×147= 22,491

I hope it helps youPlz brainlest me

Answer:

Step-by-step explanation:

1) 103×97

(100+3)×(100-3)

(a+b)(a-b) = a²-b²

=100²-3²

=10000-9=9991

2) 77×83

(80-3)×(80+3)

(a+b)-(a-b) = a²-b²

= 80²-3²

= 6400-9

= 6391

3) 205×195

(200+5)×(200-5)

(a+b)-(a-b) = a²-b²

= 200²-5²

= 40000-25

= 39975

4) 153×147

(150+3)×(150-3)

(a+b)(a-b) = a²-b²

= 150²-3²

= 22500-9

= 22491

News report about an environmental events using active and passive verb forms.pdf

Answer:

Explanation:

whawhais the angle between t  is the angle between the two

Fill in the blanks. 1.The Mundas were regarded as the original dash​

Answer:

The Munda also reside in adjacent areas of Madhya Pradesh as well as in portions of Bangladesh and the state of Tripura. They are one of India's largest scheduled tribes. Munda people in Tripura are also known as Mura, and in Madhya Pradesh they are often called Mudas.

The equation x^2 + y^2 – 6x + 4y = 4 describes a circle. Which equation describes the same circle?A. (x – 3)^2 + (y + 2)^2 = 4B. (x – 3)^2 + (y + 2)^2 = 17C. (x – 3)^2 + (y – 2)^2 = 4D. (x – 3)^2 + (y – 2)^2 = 17

Given

x² + y² - 6x + 4y = 4 describes a equation of circle

We are asked to find the standard form of equation of the circle

x² + y² - 6x + 4y = 4

Now we have find it completing square method

First separte x terms

( x² - 6x ) + ( y² + 4y ) = 4

The equation can be written as

[ x² - 2( x )( 3 ) ] + [ y² + 2( y )( 2 ) ] = 4

Adding subtracting 3², 2²

[ x² - 2( x )( 3 ) + 3² - 9 ] + [ y² + 2( y) (2) + 2² - 4 ] = 4

Using algebraic identities ( a + b)² = a² + b² + 2ab and (a - b)² = a² + b² - 2ab

( x - 3 )² + ( y + 2 )² - 13 = 4

( x - 3 )² + ( y + 2 )² = 4 + 13

( x - 3 )² + ( y + 2 )² = 17

Hence (B) ( x - 3 )² + ( y + 2 )² = 17 is the equation which describes the same circle.

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