Answer:
Option (B)
Step-by-step explanation:
Corrected Question:-Who derived the formula for solving the quadratic equation ax²+bx+c = 0 ,where a≠0 ?
Proof :-The standard quadratic equation is ax²+bx+c = 0
On dividing by a both sides then
=> (ax²+bx+c)/a = 0/a
=> (ax²/a)+(bx/a)+(c/a) = 0
=> x² +(bx/a) + (c/a) = 0
=> x²+(2/2)(bx/a) +(c/a) = 0
=> x²+(2bx/2a) +(c/a) = 0
=> x²+2(bx/2a) + (c/a) = 0
=> x² +2(b/2a)x = -c/a
=> x²+2x(b/2a) = -c/a
On adding (b/2a)² both sides then
=> x²+2x(b/2a)+(b/2a)² = (-c/a)+(b/2a)²
=> [x+(b/2a)]² = (-c/a)+(b²/4a²)
Since, (a+b)² = a²+2ab+b²
=> [x+(b/2a)]² = (-4ac+b²)/(4a²)
=> [x+(b/2a)]² = (b²-4ac)/(4a²)
=> x+(b/2a) = ±√[(b²-4ac)/(4a²)]
=> x+(b/2a) = ±[{√(b²-4ac)}/(2a)]
=> x = ±[{√(b²-4ac)}/(2a)] -(b/2a)
=> x = ±[{√(b²-4ac)}-b]/(2a)
=> x = [-b±√(b²-4ac)]/(2a)
Therefore, the roots are
[-b+√(b²-4ac)]/(2a) and [-b-√(b²-4ac)]/(2a).
This formula is known as Quadratic Formula .
This is derived by Indian Mathematician Sridharacharya.
Author:
skylar3dvv
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5Step-by-step explanation:
Answer:
Option (B)
Step-by-step explanation:
Corrected Question:-
Who derived the formula for solving the quadratic equation ax²+bx+c = 0 ,where a≠0 ?
Proof :-
The standard quadratic equation is ax²+bx+c = 0
On dividing by a both sides then
=> (ax²+bx+c)/a = 0/a
=> (ax²/a)+(bx/a)+(c/a) = 0
=> x² +(bx/a) + (c/a) = 0
=> x²+(2/2)(bx/a) +(c/a) = 0
=> x²+(2bx/2a) +(c/a) = 0
=> x²+2(bx/2a) + (c/a) = 0
=> x² +2(b/2a)x = -c/a
=> x²+2x(b/2a) = -c/a
On adding (b/2a)² both sides then
=> x²+2x(b/2a)+(b/2a)² = (-c/a)+(b/2a)²
=> [x+(b/2a)]² = (-c/a)+(b²/4a²)
Since, (a+b)² = a²+2ab+b²
=> [x+(b/2a)]² = (-4ac+b²)/(4a²)
=> [x+(b/2a)]² = (b²-4ac)/(4a²)
=> x+(b/2a) = ±√[(b²-4ac)/(4a²)]
=> x+(b/2a) = ±[{√(b²-4ac)}/(2a)]
=> x = ±[{√(b²-4ac)}/(2a)] -(b/2a)
=> x = ±[{√(b²-4ac)}-b]/(2a)
=> x = [-b±√(b²-4ac)]/(2a)
Therefore, the roots are
[-b+√(b²-4ac)]/(2a) and [-b-√(b²-4ac)]/(2a).
This formula is known as Quadratic Formula .
This is derived by Indian Mathematician Sridharacharya.
[tex]answer}[/tex]
Author:
sebastianulzc
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