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Answer:

Sin 15 Degrees

The value of sin 15 degrees is 0.2588190. . .. Sin 15 degrees in radians is written as sin (15° × π/180°), i.e., sin (π/12) or sin (0.261799. . .). In this article, we will discuss the methods to find the value of sin 15 degrees with examples.

Sin 15°: 0.2588190. . .

Sin 15° in fraction: (√6 - √2)/4

Sin (-15 degrees): -0.2588190. . .

Sin 15° in radians: sin (π/12) or sin (0.2617993 . . .)

Step-by-step explanation:

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⌬ According to the Question :

Given That-

[tex] \\ \longrightarrow\sf \: Ka = {a}^{2}c[/tex]

[tex] \\ [/tex]

★Need To Find-

• Calculate Dissociation Constant Of Acid

[tex] \\ [/tex]

★Formula To Be Used-

[tex] \small\longrightarrow \sf \: \boxed{\bf\pink{a = \frac{Percent \: Dissociation}{100} }}[/tex]

[tex] \\ [/tex]

❒ Let's Find-

[tex] = \sf \: \frac{0.5}{100} \\ [/tex]

[tex] \sf➪ \: 5 × 10⁻⁴ \\ [/tex]

[tex] \sf➪ \: C = 0.02 M \\ [/tex]

[tex] \sf➪ \: 2 × 10⁻²M \\ [/tex]

[tex] \\ {\underline{\rule{160pt}{4pt}}} [/tex]

✠Hence, Kₐ

[tex] \\ [/tex]

[tex]\longmapsto \sf \: (5 \times 10⁻⁴) ^{2} \times 2 \times 10 ^{ - 2} \\ \\ \longmapsto \sf \: 25 \times 10⁻⁸ \times 2 \times {10}^{ - 2} \: \: \: \\ \\ \longmapsto \sf \: 50 \times 10 ^{ - 10} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \longmapsto \sf \: \boxed{\bf\pink{ 5 \times {10}^{ - 9} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

❛❛ Therefore, The Dissociation Constant Of Acid Is = 5 × 10⁻⁹ ❜❜

[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]

[tex]{ \underline {\large{ \sf{Solution}}}}[/tex]

The dissociation constant of acid is Given by [tex] \rm{Ka=a^2c.}[/tex]

• [tex]\rm{a=\dfrac{Percent \: Dissosiation}{100}}[/tex]

Putting Values

[tex] \dashrightarrow\rm{ = \dfrac{0.05}{100}}[/tex]

[tex] \dashrightarrow \rm{= 5 \times 10^{-4}}[/tex]

[tex]\dashrightarrow\rm{ \green{C = 0.02 M}}[/tex]

[tex] \dashrightarrow \rm{=2 \times 10^{-2} {m}}[/tex]

Hence, K =

[tex]{ \dashrightarrow{\rm{(5 \times 10^{ -4})²×2×10^{-²} }}}[/tex]

[tex] {\dashrightarrow \rm{25 × 10^{ - 8} × 2 × 10^{-2}}}[/tex]

[tex]{ \dashrightarrow\rm{=50\times 10^{-10}}}[/tex]

[tex]{ \green{ \dashrightarrow\rm{-5 × 10^{⁹}}}}[/tex]

• Therefore, The Dissociation Constant Of Acid Is = 5 × 10⁻⁹

[tex]{ \underline{ \underline{ \rule{500pt}{5pt}}}}[/tex]

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