x divided by the sum of you y and 7​

Answer:

Answer:

\sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}sin30

∘

+cos45∘+tan180

∘

=

2

2

2

+2

Step-by-step explanation:

Given : Expression \sin30^\circ+ \cos 45\circ+ \tan 180^\circsin30

∘

+cos45∘+tan180

∘

To find : Evaluate the expression ?

Solution :

We know the values of trigonometric terms like,

\sin30^\circ=\frac{1}{2}sin30

∘

=

2

1

\cos 45\circ=\frac{1}{\sqrt2}cos45∘=

2

1

\tan 180^\circ=0tan180

∘

=0

Substitute the values in the expression,

\sin30^\circ+ \cos 45\circ+ \tan 180^\circsin30

∘

+cos45∘+tan180

∘

=\frac{1}{2}+\frac{1}{\sqrt2}+0=

2

1

+

2

1

+0

=\frac{\sqrt2+2}{2\sqrt2}=

2

2

2

+2

Therefore, \sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}sin30

∘

+cos45∘+tan180

∘

=

2

2

2

+2

Step-by-step explanation:

here's the answer mark as brainleast

Answer:

The force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another is 400.2 × 10⁻¹¹ N.

The force of gravity on a body of mass 150 kg lying on the surface of the earth is 1465.5 N.

Explanation:

1) Two objects of masses 50 Kg and 120 Kg.

∴ M = 120 Kg

   m = 50 Kg

Distance of separation, d = 10 m

Force of gravitation, F = G Mm / d²

                                     = (6.67 × 10⁻¹¹ × 120 × 50) / (10²)

                                     = 400.2 × 10⁻¹¹ N

2) Mass of the body, m = 150 Kg

Mass of the earth, M = 6 × 10²⁴ Kg

Distance of separation will be equal to the radius of the earth since the body is lying on the surface of the earth.

∴ d = Radius of the earth, R = 6.4 × 10⁶ m

Force of gravitation, F = G Mm / d²

                                     = (6.67 × 10⁻¹¹ × 6 × 10²⁴ × 150) / (6.4 × 10⁶)²

                                     = 1465.5 N

Answer:He wrote several popular works in Sanskrit and Awadhi, but is best known as the author of the epic Ramcharitmanas, a retelling of the Sanskrit Ramayana based on Rama's life in the vernacular Awadhi. Tulsidas spent most of his life in the city of Varanasi and Ayodhya.

Explaintaion:

hope it will help you

Answer:

Tulsidas complete his ramayan in Ayodhya, Varanasi and Chitrakoot.

Explanation:

Tulsidas began writing the Ramcharitmanas in Ayodhya in Vikram Samvat

Answer:

Service Asset and Configuration Management (SACM) are some commonly terms used in IT. One can use standard change to accurately describe a change to a service for which approach is pre–authorized.

The answer to the given question will be 'Standard Change'.

• The question relates to 'Change Management'.
• Standard Change can be described as a change to a service which is already pre-authorized.
• These changes are low risk.
• They are common, relatively to others.
• They follow a specified procedure or work instruction.
• Thus, the correct answer will be 'Standard Change'.