ΔΑΜΤΝ ΔΑΗΕ. In ΔΑΜΤ, ΑΜ = 6.3 cm, ΖTAM = 50°. AM 7 AT = 5.6 cm, Construct AAHE. ΑΗ 5​

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Answer:

ΔAMT∼ΔAHE.

AHAM=HEMT=AEAT=57

In ΔAMT, AM=6.3 cm,AT=4.9 cm and ∠A=120∘.

Draw a ray from point A forming an acute angle with AT on the opposite side of M. Divide the ray into 7 equal parts such that AS1=S1S2=S2S3=S3S4=S4S5=S5S6=S6=S7

Join S7 with T. From S5, draw a line ∥ to S7T and let it intersect AT at E.

Draw EH∥TM.

ΔAEH is the required similar triangle.

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