Divide the following[tex](6x {}^{3} + 4 {}^{2} + 2x + 2) \div 2x [/tex]​

Answers 1

Answer:

Step-by-step explanation:

first,

6xcube +16 + 2x+2/2x6xcube +18 +2x/2x

take 2 common on numerator

2(3cube +18 + 2x)/2x

then, 2 and 2 will cancel out  give you the equation

(3cube + 18 + 2x)/x

you can simplify it more............

writing it as.............

3x + 1 +(9/x).

hope you understand it...

Thank you........

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