The number of zeroes in the square of 233000​

Answer:

This is textbook answer

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Explanation:

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Explanation:

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शिवाजी महाराज

घोषना प्रौढप्रताप पुरंदर क्षत्रिय कुलावतंस सिंहासनाधीश्वर गो ब्राह्मण प्रतिपालक भोसले कुलदीपक हिन्दवी साम्राज्य संस्थापक मुघल जन संघारक श्रीमान योगी योगिराज

बुद्धिवंत कीर्तिवंत कुलवंत नीतिवंत धनवंत सामर्थ्यवंत धर्मधुरंधर श्रीमंत श्रीमंत श्रीमंत महाराजाधिराज

[tex]\huge\red{➳Ṧřîⅉꫝᾇñ ࿐} [/tex]

Answer:

10

Explanation:

4 hours x 12 days=48 total hours worked

48 hours x 10 men=480 man/hours

1 man/480 total hours=1/480th of the work done per man per hour

8 x 6 x 1/480=1/10 work done per day

1 work / 1/10 work done per day=10 days necessary to finish the work

Given :

10 persons work 8 hours per day and complete work in 6 days.

To find :

The number of days taken to complete the same work by 5 persons working 4 hours per day.

Solution :

• 10 persons working 8hrs per day can complete the work in 6 days.

• 10 persons working 1hr per day can complete the work in (6x8)days.                                        

• 1 person working 1hr a day can complete the work in  (6x8x10)days.                      

• 1 person working 4hrs a day can complete the work in                          [(6x8x10)/4]days.

Therefore, 5 persons working 4hrs a day can complete the work in

            [(6x8x10)/(4x5)]days

            =  (480/20)days = 24 days

5 persons working 4hrs per day will take 24 days to complete the work.

Answer:

[tex]y=\sqrt{1-x^{2} } +3\sqrt{2x} \\y=-\sqrt{1-x^{2} } +3\sqrt{2x}[/tex]

Step-by-step explanation:

Given the equation is

[tex]x^{2} +(y-3\sqrt{2x} )^{2} =1[/tex]

Subtract [tex]x^{2}[/tex] from both sides of the equation

[tex](y-3\sqrt2{x} )^{2} +x^{2} -x^{2} =1-x^{2}[/tex]

Subtracting [tex]x^{2}[/tex] from itself leaves [tex]0[/tex]

[tex](y-3\sqrt{2x} )^{2} =1-x^{2}[/tex]

Take the square root of both sides of the equation

[tex]\sqrt{(y-3\sqrt{2x} )^{2} } =\sqrt{1-x^{2} }[/tex]

The square root operation always gives one positive number, and one negative number.

[tex](y-3\sqrt2{x} )=\sqrt{1-x^{2} } \\(y-3\sqrt{2x} )=-\sqrt{1-x^{2} }[/tex]

take[tex]-3\sqrt{2x}[/tex] on the right side then the value of [tex]y[/tex] is

[tex]y=\sqrt{1-x^{2} } +3\sqrt2{x}[/tex]

[tex]y=-\sqrt{1-x^{2} } +3\sqrt{2x}[/tex]

Then equation is solved and

[tex]y=\sqrt{1-x^{2} } +3\sqrt{2x} \\y=-\sqrt{1-x^{2} } +3\sqrt{2x}[/tex]