Q.1)Find the common factors of the given terms. a. 9a3b2, 27 a2b3 b. -8x3, 4x2y, 16xy c. 10m2n2, 40m3n2, 20mn d. -7p2, 28p2t3, 14p3t3 e. 19pqr, 95p2q2r2, 57p2 f. 18x2yz, 6xy2z

Answers 1

Answer:

Solution :-

1) a. 9a³b², 27a²b³

9a³b² = 3 × 3 × a × a × a × b× b

27a²b³ = 3 × 3 × 3 × a × a × b × b × b

∴ Common factors = 3 × 3 × a × a × b × b

= 9a²b²

b. - 8x³, 4x²y, 16xy

- 8x³ = - 2 × 2 × 2 × x × x × x

4x²y = 2 × 2 × x × x × y

16xy = 2 × 2 × 2 × 2 × x × y

∴ Common factors = 2 × 2 × x × y

= 4xy

c. 10m²n², 40m³n², 20mn

10m²n² = 2 × 5 × m × m × n × n

40m³n² = 2 × 2 × 2 × 5 × m × m × m × n × n

20mn = 2 × 2 × 5 × m × n

∴ Common factors = 2 × 5 × m × n

= 10mn

d. - 7p², 28p²t³, 14p³t³

- 7p² = - 7 × p × p

28p²t³ = 2 × 2 × 7 × p × p × t × t × t

14p³t³ = 2 × 7 × p × p × p × t × t × t

∴ Common factors = 7 × p × p

= 7p²

e. 19pqr, 95p²q²r², 57p²

19pqr = 1 × 19 × p × q × r

95p²q²r² = 5 × 19 × p × p × q × q × r × r

57p² = 3 × 19 × p × p

∴ Common factors = 19 × p

= 19p

f. 18x²yz, 6xy²z

18x²yz = 2 × 3 × 3 × x × x × y × z

6xy²z = 2 × 3 × x × y × y × z

∴ Common factors = 2 × 3 × x × y × z

= 6xyz

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