Jai played a game on the number line using a token. He began the game with the token at O as shown below. He moved the token from 0 to -9 and then to 10. Which of the following number sentence correctly represents the OVERALL movement of the token? A. (-9) + 10 B. (-9) - 0 C. (-9) + 20 D. (-9) + 19

Narmada rises from Amarkantak Plateau in Anuppur district Madhya Pradesh. It forms the traditional boundary between North India and South India and flows westwards over a length of 1,312 km (815.2 mi) before draining through the Gulf of Khambhat into the Arabian Sea, 30 km (18.6 mi) west of Bharuch city of Gujarat.

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C-14, Jawahar nagar,

Palghar

17 Jan 2022

Dear,

I saw a accident of mumbai express. You are also doing shift job by train. So, I want to only tell you that when you are going in train or coming out of the train so be careful. Take care

Manisha

please mark me as brainleist

Answer:

u r Manav staying at 2/31 Imperial Heights, Doctor Ambedkar road, Pali. you happen to read the following news item in the New Mumbai Express write a letter to the police commissioner of Mumbai expressing your concern at the lack of safety of women in the city mention the major that can be adopted to solve the problem.

Mira Jangid

2/31 Imperial

Height,Ambedkar

Road, Parel.

Maharashtra-422008

Date-26 January 2022.

To

Police Commissioner

Maharashtra- 422009.

Subject :- Women's safety.

Respected sir,

Hope this letter find you well. I am Mira Jangid living at 2/31 Imperial height, Dr Ambedkar Road, Parel.

I was just happened to read the news items in Mumbai Express. I am writing this letter to you to draw your attention towards the lack of safety of women in our society . Everyday we have seen a new crime regarding womens.

I know that you will take action regarding the women safety issue.

Thank you!

Your faithfully,

Mira Jangid.

Answer:

पहर

बिधि

भोरी

पाई

सौह

माखन

स्याम

लरिका

गैमन

जसोदा

Answer:

here is your answer hope it helps

Given:

Speed of swimmer [tex]V_{s}=0.6 m/s[/tex]

Width of the river [tex]=50m[/tex]

Speed of the water in river [tex]V_{w} =0.36m/s[/tex]

To find:

The direction in which he swimmer should swim in order to reach the exact opposite point.

Solution:

From the figure, lets assume that the swimmer starts swimming from [tex]O[/tex] with a speed [tex]V_{s}=0.6m/s[/tex]. According to the question, the swimmer wants to reach the point [tex]P[/tex] but, as we know, the river is flowing with a velocity [tex]V_{w}=0.36m/s[/tex].

If the swimmer swims in the direction [tex]OP[/tex], he will lose the trajectory of the path and miss the point [tex]P[/tex] by flowing in the direction of the river.

To cover this gap, the swimmer needs to swim in the direction opposite to the flow of the river at an angle θ with the horizontal.

Lets assume, the target point of the swimmer be the point [tex]O'[/tex] which makes an angle θ with the river. Hence, with the presence of the flow of river, swimmer reaches the required point [tex]P[/tex].

Now,

In Δ[tex]OAO'[/tex], we have, ∠[tex]AOO'=[/tex] θ, Hence,

[tex]cos[/tex]θ  [tex]=\frac{OA}{O'O}[/tex]

[tex]cos[/tex]θ  [tex]=\frac{0.36}{0.6}[/tex]

[tex]cos[/tex]θ  [tex]=0.6[/tex]

Hence,

θ [tex]=cos^{-1}(0.6)[/tex]

θ [tex]=53^{o}[/tex]

The swimmer needs to travel with an angle of [tex]53^{o}[/tex] with respect to the origin with the horizontal.

Final answer:

Hence, the swimmer should travel in the direction opposite to the flow of river at an angle of 53° with respect to the horizontal.