The age of students in a group are in A.P. having comman difference of 3 months. The age of the youngest student in a group is 12 years Sum of ages of all the students in a 375 years. find the number of Students in the group group​

Answer:

60.05 gm /mol

Explanation:

Molar mass ={2×12.011(C)+4×1.00794(H)+2×15.999(O)}.g.mol

−1

=60.05.g.mol

The molar mass of acetic acid is 60.05⋅g⋅mol

[tex]\star[/tex] Concept

Molecular Mass is the sum of individual atoms in the molecule .Start the question by writing chemical formula of Acetic acid and the add the molar mass of individual atoms.

Complete step by step answer :

[tex]\sf\implies[/tex] Chemical formula of Acetic acid [tex]\rightarrow[/tex] (C [tex]H_{3}[/tex] COOH)

[tex]\rightarrow[/tex] Atomic mass of C = 12

[tex]\rightarrow[/tex] Atomic mass of O = 16

[tex]\rightarrow[/tex] Atomic mass of H = 1

Molecular mass :

• Since , there are 2 carbon atoms

[tex]\rightarrow[/tex] 2 × atomic mass of C

• Since, there are 2 atoms of oxygen

[tex]\rightarrow[/tex] 2 × atomic mass of O

• Since, there are 4 atoms of hydrogen

[tex]\rightarrow[/tex] 4 × atomic mass of one hydrogen atom

[tex]\sf\implies[/tex] 2× 12 + 2 × 16 + 4 × 1

[tex]\sf\implies[/tex] 24 + 32 + 4

[tex]\sf\implies[/tex] 60

Since , Molecular mass is donated by u

[tex]\therefore[/tex] Molecular mass of Acetic acid is 60 u.

Answer:

वैज्ञानिक के रूप में एमएस स्वामी यानी मोनकोम्पू सांबासिवन स्वामीनाथन को 'हरित 'क्रांति' का जनक कहा जाता है ।

Answer:

Astha borrowed approx. [tex]\text{Rs}30021[/tex].

Step-by-step explanation:

Let the sum Astha borrowed be [tex]$x$[/tex].

Then, using [tex]S.I=\frac{p*r*t}{100}[/tex], where [tex]p,r,t[/tex] are principle, rate  & time respectively.

[tex]$$\begin{aligned}&\left(\frac{x \times 7 \times 2}{100}\right)+\left(\frac{x \times 6 \times 4}{100}\right)+\left(\frac{x \times 9 \times 1}{100}\right)=14110 \\&\left(\frac{14 x}{100}+\frac{24 x}{100}+\frac{9 x}{100}\right)=14110 \\\frac{47 x}{100}=14110 \\& x=\frac{14110\times 100}{47}=30021 .27\end{aligned}$$[/tex]

Hence, sum borrowed[tex]$=$ Rs 30021.27[/tex] or approximately Rs. [tex]30021[/tex].

#SPJ2

Answer:

Total amount of money Astha borrowed= Rs 17000

Step-by-step explanation:

In the above question:

Given:

1. R(rate)= 7%

   T(time)= 2 years

2. R(rate)= 6%

    T(time)= 4 years

3.    R(rate)= 9%

    T(time)= 5 years

To find:

Total amount borrowed?

Solution:

Total interest= Rs 14110

We know, the formula for Simple interest as:

S.I= P×R×T/100

P= principle amount(here borrowed amount)

R= Rate of interest

T= Time

Let the total amount borrowed be 'x'

Then, total amount borrowed at the end of 11years will be;

S.I= P1×R1×T1/100+P2×R2×T2/100+P3×R3×T3/100

14110= x×7×2/100+x×6×4/100+x×9×5/100

14110= 14x/100+24x/100+45x/100(common denominator)(x is also common)

14110= 14x+24x+45x/100          

14110= 83x/100

  83x= 14110×100

      x= 1411000/83

      x= 17000

The amount of money she borrowed was Rs17000

#SPJ2

Answer:

The Equator is the line of 0 degrees latitude. Each parallel measures one degree north or south of the Equator, with 90 degrees north of the Equator and 90 degrees south of the Equator. The latitude of the North Pole is 90 degrees N, and the latitude of the South Pole is 90 de

Explanation:

please mark me as a brainlist please

Answer:

0°

Explanation:

The value of equator is 0° and the latitude of the poles are 90°N and 90°S (Fig.