Write the following fractions in ascending order: 2/3,2/7,2/11,2/5,and2/9
Answers 2
Answer:
ascendeing order
Step-by-step explanation:
2/3,2/5,2/7,2/9and 2/11
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Author:
dakota401
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Answer:
The ascending order will be[tex]\frac{2}{11} ,\frac{2}{9} ,\frac{2}{7} ,\frac{2}{3}[/tex]
Step-by-step explanation:
Given: [tex]2/3,2/7,2/11,2/5,and2/9[/tex]
We have to arrange the above fractions in ascending order.
- For this, we will make the denominator of the above fractions the same, and then we will arrange the above fractions in ascending order.
We are solving in the following way:
We have,
[tex]2/3,2/7,2/11,2/5,and2/9[/tex]
First, we will find the lcm of 3, 7, 11, and 9.
The lcm of 3, 7, 11, and 9 is 693.
So,
[tex]=>\frac{2}{3} ,\frac{2}{7} ,\frac{2}{11} ,\frac{2}{9}\\\\=>\frac{2}{3}\times\frac{231}{231} ,\frac{2}{7}\times\frac{99}{99},\frac{2}{11}\times\frac{63}{63},\frac{2}{9}\times\frac{77}{77}\\\\=>\frac{462}{693} ,\frac{198}{693} ,\frac{126}{693},\frac{154}{693}[/tex]
Because the denominators of all four integers are the same, they will be ordered in ascending order in the same manner that their numerators are growing.
[tex]126<154<198<462[/tex]
Therefore the ascending order is:[tex]\frac{2}{11} <\frac{2}{9} <\frac{2}{7} <\frac{2}{3}[/tex]
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giannauvua
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