Answer:
Let tanx = t
sec^2xdx = dt
dx = dt/sec^2x
integration (√t×cosec^2x)/sec^2x dt
integration √(t)/tan^2x dt
integration 1/t√t dt
integration (t)^-3/2 dt
[ (t)^-1/2 ] / -1/2 + c
-2(1/√tanx) + c
Ans : -2(1/√tanx) + c
.
.
Hope it helps you .
Author:
chayabanz
Rate an answer:
3