integrate √tanx/sin^2x dx​

  • matematika

    Subject:

    Math
  • Author:

    olsen
  • Created:

    1 year ago

Answers 1

Answer:

Let tanx = t

sec^2xdx = dt

dx = dt/sec^2x

integration (√t×cosec^2x)/sec^2x dt

integration √(t)/tan^2x dt

integration 1/t√t dt

integration (t)^-3/2 dt

[ (t)^-1/2 ] / -1/2 + c

-2(1/√tanx) + c

Ans : -2(1/√tanx) + c

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