Frame the quadratic equation 4 and 7​

  • matematika

    Subject:

    Math
  • Author:

    jax32
  • Created:

    1 year ago

Answers 2

The standard quadratic equation using the given set of solutions {−4,7} is y=x2−3x−28 y = x 2 - 3 x - 28 .

The quadratic equation will be[tex]x^2 -11x +28 =0[/tex]

Step-by-step explanation:

To frame the quadratic equation using the solutions as 4 and 7, we can go in the reverse order of finding the solution.

  • Let x =  4, and x = 7
  • Then solutions can be written as [tex](x-4)[/tex] and [tex](x-7)[/tex]
  • Now, taking the product of the two terms and equating to zero

[tex](x-4)(x-7)=0[/tex]

  • On multiplication, we obtain,

[tex]x^2-7x-4x+28 = 0[/tex]

[tex]x^2 -11x +28 =0[/tex]

  • Hence, the desired quadratic equation is [tex]x^2 -11x +28 =0[/tex]

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