15 मी लंबे एक कमरे के फर्श को ढकने के लिए 15 सेमी x 12 सेमी आकार की 7500 टाइलों की आवश्यकता होती है। कमरे की चौड़ाई ज्ञात कीजिए।​

Answer:

Carbon fibre can be called a wire of carbon, but as carbon itself is classified as a nonmetal, hence carbon fibre is also a nonmetal. Also, merely possession of any one property, does not satisfy the criteria for a material to be called a metal. other properties like conductivity, luster position in periodic table etc.

Answer:

In this poem 'Nine Gold Medals', the poet, David Roth has presented the idea of empathy and how human values are as important as the spirit of competition. The poem presents the situation of a race, where the contestants leave aside their desire to win the medal to help a smaller and weaker contestant.

Explanation:

please give me brilliant.

The message conveyed by the poet here is that the world now needs more cooperation and collaboration than competition.and helping others can do a lot of good not only to the person who is being helped but also to the person who is helping. It underlines the idea of empathy and human values. It gives us the message that what values most in life is the sense of sharing other’s pain and sorrow and trying to cheer up and encourage the weak and the fallen.

It presents an imaginary situation of a race in which contestants are ready to compete against one another to win the Gold medal. When they see a weak contestant fall

Height of the building = 49 m

Range of the projectile = 24.5 m

A) Time taken by ball :

Time taken by ball to reach the ground is given by;

[tex]\sf:\implies\:t=\sqrt{\dfrac{2H}{g}}[/tex]

• H denotes height
• g denotes acceleration due to gravity

[tex]\sf:\implies\:t=\sqrt{\dfrac{2\times 49}{9.8}}[/tex]

[tex]\sf:\implies\:t=\sqrt{\dfrac{98}{9.8}}[/tex]

[tex]\sf:\implies\:t=\sqrt{10}[/tex]

[tex]:\implies\:\underline{\boxed{\bf{\red{t=3.16\:s}}}}[/tex]

B) Initial velocity of the ball :

Horizontal distance covered by the ball before hitting the ground is given by;

• Note that here vertical component of the initial velocity will be zero as it is the case of horizontal projectile.
• So the initial will only have horizontal component [tex]\sf{u_x}[/tex]

[tex]\sf:\implies\:R=u_x\times t[/tex]

[tex]\sf:\implies\:24.5=u_x\times 3.16[/tex]

[tex]\sf:\implies\:u_x=\dfrac{24.5}{3.16}[/tex]

[tex]:\implies\:\underline{\boxed{\bf{\blue{u_x=7.75\:ms^{-1}}}}}[/tex]

C) Final velocity of the ball :

Velocity with which ball strikes the ground will have two components. i.e, Horizontal and vertical (downward).

• Horizontal component [tex]\sf{v_x}[/tex]
• Vertical component [tex]\sf{v_y}[/tex]

[tex]\sf:\implies\:v=\sqrt{{v_x}^2+{v_y}^2}[/tex]

• Horizontal component of the velocity will remain same.

[tex]\sf:\implies\:v=\sqrt{{u_x}^2+{gt}^2}[/tex]

[tex]\sf:\implies\:v=\sqrt{{7.75}^2+{(10\times 3.16)}^2}[/tex]

[tex]\sf:\implies\:v=\sqrt{60+998.56}[/tex]

[tex]\sf:\implies\:v=\sqrt{1058.56}[/tex]

[tex]:\implies\:\underline{\boxed{\bf{\gray{v=32.53\:ms^{-1}}}}}[/tex]

• Height of the building = 49 m
• Range = 24.5 m
• We are asked to find the time it takes for thr ball to reach the ground & the velocity of the ball just before it strikes the ground

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According to the Question :

• The time taken is given by t = √(2H/g)

⇒ t = √(2H/g)

• H = 49 m
• g = 9.8 m/s²

⇒ t = √[(2×49)/9.8]

⇒ t = √(98/9.8)

⇒ t = √10 seonds

• The initial velocity can be found with the help of the relation R = ut

⇒ R = ut

• R = 24.5 m
• t = √10 sec

⇒ 24.5 = u × √10

⇒ (24.5)/(√10) = u

⇒ u = 7.75 m/s

• The velocity of the ball just before it strikes the groumd is given by the magnitude of its components

⇒ v = √vx +vy

• vx = 10 m/s
• vy = √2gh = √2×10×49 = √980 m/s

⇒ v = √(100 + 980)

⇒ v = √(1080)

⇒ v = 32.8 m/s

Therefore the time taken by the ball is √10 sec & the initial velocity of the ball is 7.75 m/s & the velocity of the ball just before it strikes the ground is 32.8 m/s

Answer:

The first is simply called the Selection Tool, which can be selected by clicking on this icon, located at the top of the Toolbar.

Answer:

quick access toolbar is the correct answer.

Explanation:

pls mark me brainliest.