Find the square of the following number. 0.003 The first and the right answer will be marked as brainliest

Answers 1

(0.003) x(0.003)

= (3/1000) x(3/1000)

=(9/1000000)

=0.000009

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A particle moves in a straight line with velocity function v(t) = 2√t+3 cms¯¹, t > 0. a Find the average acceleration from t = 1 to t = 4 seconds.​

V=∣t−4∣

V=t−4 for t>4

V=−(t−4) for t<4

For t∈[0,4]

v=−t+4

a=−1m/s2

Since acceleration is uniform at t=0,v=4m/s

x=21×1×16

x=8m

For t>0, v=t−4

Acceleration =1m/s

s=21×4×4=8m

Total distance =16m

Correct option is B)

V=∣t−4∣

V=t−4 for t>4

V=−(t−4) for t<4

For t∈[0,4]

v=−t+4

a=−1m/s

2

Since acceleration is uniform at t=0,v=4m/s

x=

2

1

×1×16

x=8m

For t>0, v=t−4

Acceleration =1m/s

s=

2

1

×4×4=8m

Total distance =16m

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