If the lcm of two prime numbers x and y is 221, where y is bigger than x , then the value of 4y-3x will be:
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Subject:
Math -
Author:
paconielsen -
Created:
1 year ago
Answers 2
Answer:
lcm of two prime numbers x and y is 221
so , x*y=221=17*13
as , y is bigger than x
so , here y=17 and x=13
so , 4y-3x
=4*17-3*13
=68-39
=29
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Author:
adaphelps
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Rate an answer:
3
Icm of two prime numbers x and y is 221
Icm of two prime numbers x and y is 221so, x*y=221=17*13
Icm of two prime numbers x and y is 221so, x*y=221=17*13as, y is bigger than x
Icm of two prime numbers x and y is 221so, x*y=221=17*13as, y is bigger than xSo, here y=17 and x=13
Icm of two prime numbers x and y is 221so, x*y=221=17*13as, y is bigger than xSo, here y=17 and x=13so, 4y-3x
Icm of two prime numbers x and y is 221so, x*y=221=17*13as, y is bigger than xSo, here y=17 and x=13so, 4y-3x=4*17-3*13
Icm of two prime numbers x and y is 221so, x*y=221=17*13as, y is bigger than xSo, here y=17 and x=13so, 4y-3x=4*17-3*13=68-39
=29
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Author:
schaefer
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3