Jinal saves rupees 1600 during the first year rupees 2100 in the second year 2600 in the third year if she continues her saving in this same pattern in how many years will she save rupees 38500??pls solve step by step ​

Answers 1

Answer:

Common difference 500

a = 1600

l = 38500

Number of years = [38500-1600]/500

Number of years = 73.8

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modsirisha

Grade 9

follow

1600,2100,2600,....

this is an arithmetic progression with

a= 1600, d= 500

sum of A.P.= n/2[2a+(n-1)d]

38500= n/2[3200+(n-1)500]

770= n[32+(n-1)5]

770=32n + 5n² - 5n

5n²+27n -770=0

n=10,(-77/5)

years can't be negative so 10 years

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