If p(x) =5-4x+2x², find i p(0) ii p(3) iii p(-2)​

Answers 2

Answer:

[tex]We \: have \: P \: (x) \: =5-4x+2x². Hence \\ \\ we \: get \: the \:  P(0)=5,P(3)= \\ \\ 11,P(-2)=21. \\ [/tex]

[tex]p(x) =5-4x+2x² \\ \\ p(0) = 5 - 4(0) + 2( {0)}^{2} \\ \\ = 5 - 0 + 0 \\ \\ = 5[/tex][tex] \\ [/tex][tex]p(x) =5-4x+2x² \\ \\ p(3) = 5 - 4(3) + 2( {3)}^{2} \\ \\ = 5 - 12 + 18 \\ \\ = 5 + 6 \\ \\ = 11[/tex][tex] \\ [/tex][tex]p(x) =5-4x+2x² \\ \\ p( - 2) = 5 - 4( - 2) + 2( { - 2)}^{2} \\ \\ = 5 + 8 + 8 \\ \\ = 21[/tex]

If you know the answer add it here!

Can't find the answer?

Log in with Google

or

Forgot your password?

I don't have an account, and I want to Register

Choose a language and a region
How much to ban the user?
1 hour 1 day 100 years