bina x ka man nikale gyat kijiye[tex]4x {}^{2} + x + 5 = 0 \: \: bina \: x \: ka \: man \: nikale \: gyat \: karo[/tex][tex]1) \: \: \frac{1}{ \alpha } + \frac{1}{ \beta } [/tex][tex]2) \: \: \alpha {}^{2} + \beta {}^{2} [/tex]​

Answers 1

Answer:

To find the value of

α

1

+

β

1

We know that equation ax

2

+bx+c=0

Then sum of roots =

a

−b

and product of roots=

a

c

From the given quadratic equation,

α+β=−

4

3

and αβ=

4

7

Therefore,

α

1

+

β

1

=

αβ

α+β

=

4

7

4

3

=−

7

3

α

1

+

β

1

=−

7

3

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