Step-by-step explanation:
Given→ AP→4C3+5C3+6C3...12C3
Solution→ a=4C3 d=a2 - a1 n=?
=5C3 - 4C3
=1C3
12C3=a+(n-1)d
12C3=4C3+(n-1)1C3
12C3 - 4C3=(n-1)1C3
8C3=(n-1)1C3
8C3/1C3=n-1
8=n-1
8+1=n
9=n
So, number of terms are 9
S=n/2[2a+(n-1)d]
S=9/2[2*4C3+(9-1)1C3]
S=9/2[8C3+(8)1C3]
S=9/2[8C3+8C3]
S=9/2[16C3]
S=9[8C3]
S=72C3
So,the answer is 72C3.
Author:
ivyyjhu
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