Directions: Refer to the figure on the right and fill in the blanks with the correctanswer.Given: ABCD is a parallelogram. BD and CA are diagonals.6. ∠B ≅7. BC II8. BA ≅9. ∆ABC ≅ ​

Answer:

This is the answer

Explanation:

Hope it helped u

Answer:

#include <iostream>

#include <iomanip>

#define MAX 50

using namespace std;

int main() {

   int a[MAX], b[MAX], sum[MAX];

   int n,m,i,j;

   cout<<"\nEnter number of elements in A: ";

   cin>>n;

   cout<<"\nEnter number of elements in B: ";

   cin>>m;

   cout<<"\nEnter elements of A: ";

   for(i=0;i<n;i++)

       cin>>a[i];

   cout<<"\nEnter elements of B: ";

   for(i=0;i<m;i++)

       cin>>b[i];

   if(n>m)

   j=n;

   else

   j=m;

   for(i=0;i<j;j++)

       sum[i]=a[i]+b[i];

   cout<<"\nThe sum of elements of the two arrays is: ";

   for(i=0;i<j;i++)

       cout<<sum[i]<<setw(5);

   return 0;

}

Explanation:

1. Declare arrays and variables to store the input data.
2. Take the number of elements and the elements of both the arrays as input from the user.
3. Store the elements in the respective array.
4. Add the individual elements of one array with the corresponding element of the other array.
5. Store the sum in another array.
6. Print the array sum as the output.

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Answer:

The answer is 20.865 [ 21 sec approximately ]

Step-by-step explanation:

Given data

A chocolate fudge machine uses 4 different nozzles to make a glass of fudge A for vanilla ice-cream, B for chocolate ice-cream, C for fruits and nuts and D for fresh crèam

A can fill the glass in 30 sec;  B can fill the glass in 40 sec

C can fill the glass in 20 sec;  D can fill the glass in 10 sec  

To fill a glass the machine opens each nozzle one by one for a second

in the sequence A B C D A B C D A B C D...  

Here we need to find in how many seconds the machine can make a chocolate fudge ?

As per the given sequence  

For 1st sec  A nozzle can fill  [tex]\frac{1}{30}[/tex] of the glass

For 2nd sec B nozzle can fill [tex]\frac{1}{40}[/tex] of the glass

For 3rd sec C nozzle can fill [tex]\frac{1}{20}[/tex] of the glass

For 4th sec D nozzle can fill [tex]\frac{1}{10}[/tex] of the glass

Therefore,

for 4 sec the part of the glass can be filled = [tex]\frac{1}{30} +\frac{1}{40} + \frac{1}{20} + \frac{1}{10}[/tex]

                                                                       = [tex]\frac{4+3+6+10}{120} = \frac{23}{120}[/tex]  

In 4 sec [tex]\frac{23}{120}[/tex] of the glass can be filled

Therefore, time taken to fill 1 glass =  [tex]\frac{120}{23} (4)= \frac{388}{23} = 20.865[/tex] sec

#SPJ3

Answer:

19

Step-by-step explanation:

Answer:

Answer:

सुरेश/सुरेखा पाटील, 75, मजगे नगर, हिंगोली से व्यवस्थापक, निकिता पब्लिकेशन, एमआयडीसी, लातूर-413512 को पुस्तक की मांग करते हुए पत्र लिखता/लिखती है।

सुरेश/सुरेखा पाटील,75,मजगे नगर,हिंगोली से व्यवस्थापक, निकीता पब्लिकेशन, एमआयडीसी,लातूर-413512को पुस्तक की माँग करते हुए पत्र लिखता/लिखती है।