Subject:
MathAuthor:
jordynsextonCreated:
1 year agoAnswer:
Solution
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Correct option is A)
Here AB is a diameter of the circle with centre O, two tangents PQ and RS drawn at points A and B respectively.
Radius will be perpendicular to these tangents.
Thus, OA ⊥ RS and OB ⊥ PQ
∠OAR=∠OBP=∠OBQ=90
0
Therefore,
∠OAR=∠OBQ (Alternate interior angles)
∠OAS=∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.
Author:
aidynptaq
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2Answer:
the tangents drawn at A and B are
Author:
josiah1uhz
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10