In the adjoining diagram AB is perpendicular to PX. If CXB is a straight line and AP = BP, prove that CB= CX+XA​

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Answers 1

Step-by-step explanation:

In △OAP and △OBQ,

AP=BQ(given)

∠OAP=∠OBQ=90

∘

∠OAP=∠OBQ(vertically opposite angles)

∴△OAP is congruent to △OBQ by AAS axiom

∴OA=OB by C.P.C.T.

and OP=OQ by C.P.C.T

⇒O is the midpoint of line segments AB and PQ

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