boy 1.7 m tall is standing on a horizontal ground, 50m away from a building. The angle of elevation of the top of the building from his eye is 60° . Calculate the height of the building (Take √3 = 1.73)​

Answers 2

Step-by-step explanation:

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class 10 chapter 9

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Answer:

Let PR be the building and AB be the boy

In ∆PQR, tan600 = PQ/50

⇒ √3 = PQ/50

⇒ PQ = 50√3m

Height of the building = PR = PQ + QR

= (50√3 + 1.7)m

= 88.2m

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