40 markers for 9.63$ (A) 14.99$ for 64 markers (B) 3.18$ for 10 markers (C)-find how much each marker is-What is the best buy for money per marker?

Answer:

The full form of IRCTC is the Indian Railways Catering and Tourism Corporation. IRCTC is an Indian Railway subsidiary established by the Ministry of Railways to manage Indian railway catering, online ticketing and tourism operations.

Answer:

Indian Railway Catering and Tourism Corporation

Answer:

Crystallization or crystallisation is the process by which a solid forms, where the atoms or molecules are highly organized into a structure known as a crystal. Some of the ways by which crystals form are precipitating from a solution, freezing, or more rarely deposition directly from a gas.

Step-by-step explanation:

[tex]15.625 = \frac{15.625}{1000} [/tex]

[tex] \frac{15625}{1000 } = \frac{3125}{200} [/tex]

[tex] \frac{3125}{200} = \frac{625}{40} [/tex]

[tex] \frac{625}{40} = \frac{125}{8} [/tex]

125/8

help with cwpriya

Answer:

(I) 0.1n2+7.7n-7.8

(2) 8.2cm

Step-by-step explanation:

hope this will help you!

Answer:

[tex]S_{n-1}=0.1n^2 +7.7n - 7.8[/tex]

The diameter of the roll when one sheet is rolled over = 8.2cm

Step-by-step explanation:

(i) Given [tex]S_n = 0.1n^2 + 7.9n[/tex]

To find [tex]S_{n-1}[/tex], substitute the value of ‘n’ as ‘n-1’ in the above equation

Then,

[tex]S_{n-1} = 0.1(n-1)^2 + 7.9(n-1)[/tex]

= [tex]0.1(n^2 -2n+1) +7.9n-7.9[/tex]

=[tex]0.1n^2 -0.2n+0.1 +7.9n-7.9[/tex]

=[tex]0.1n^2 +7.7n - 7.8[/tex]

Hence, [tex]S_{n-1}=0.1n^2 +7.7n - 7.8[/tex]

(ii) Given,

Diameter of the core = the first term of the AP = [tex]a_1[/tex]

Twice the thickness of the paper  = common difference= d

When one sheet of paper is rolled over the core,

Then the new diameter of the roll = [tex]a_1+d[/tex], the second term of the AP([tex]a_2[/tex])

To find [tex]a_2[/tex]

We have [tex]S_n = 0.1n^2 + 7.9n[/tex]

[tex]S_1 = first term = a_1 = 0.1x1 +7.9 = 0.1+7.9 = 8[/tex]

[tex]S_2 = a_1 + a_2[/tex]

[tex]0.1 x 2^2 + 7.9 x2 = 8 +a_2[/tex]

[tex]0.4+15.8 = 8+a_2[/tex]

[tex]16.2 = 8+a_2[/tex]

[tex]a_2 = 8.2[/tex]

Hence, the diameter of the roll when one sheet is rolled over = 8.2cm