Write the disjunction of Roses are red. Blacks are blue​

Step-by-step explanation:

64×9=576. 64×6=384. 576÷384=0.66666666666

Answer:

The value of  [tex]64\sqrt[3]{x^{9} }[/tex] ÷ [tex]\sqrt[3]{64x^{6} }[/tex] is 16x.

Step-by-step explanation:

The nth root of 'x' can be written as

[tex]\sqrt[n]{x} =x^{\frac{1}{n} }[/tex]  where n is a integer.

[tex]\sqrt{xy} = \sqrt{x} *\sqrt{y}[/tex]

[tex]\sqrt[n]{x^{a} } = x^{\frac{a}{n} }[/tex]

Four cube is sixty four.

that is 4³ = 4×4×4 = 64

then [tex]\sqrt[3]{64} =(64)^{\frac{1}{3} } =(4^{3})^{\frac{1}{3} } = 4[/tex]

We have to find the value of [tex]64\sqrt[3]{x^{9} }[/tex] ÷ [tex]\sqrt[3]{64x^{6} }[/tex]

Given that [tex]64\sqrt[3]{x^{9} }[/tex] ÷ [tex]\sqrt[3]{64x^{6} }[/tex]

In general [tex]\sqrt[3]{x} = x^{\frac{1}{3} }[/tex]

[tex]\sqrt[3]{x^{9} } = x^{\frac{9}{3} } = x^{3}[/tex]

[tex]\sqrt[3]{64x^{6} } =(4^{3} )^{\frac{1}{3} }*(x^{6})^{\frac{1}{3} } } = 4x^{2}[/tex]

Now the expression becomes,

64x³÷ (4x²) = 16x

The value of  [tex]64\sqrt[3]{x^{9} }[/tex] ÷ [tex]\sqrt[3]{64x^{6} }[/tex] is 16x.

Answer:

I is the answer

Hope it Helps

• When we rotate an object/alphabet fixing its angle (other than 360 degrees) at a fixed point and we get the same figure it is said to have rotational symmetry of order more than 1.
• In the word QUADRILATERAL alphabet Q, U, A, D, R, L, T, E have no rotational symmetry While alphabet I have rotational symmetry of order more than 1.
• Therefore, In the word QUADRILATERAL alphabet, I show the rotational symmetry of order more than 1.

Answer:

Advertising is all about building brands.

Brands are an integral part of advertising. The significance of a brand and the need to promote the uniqueness of a product is a key part of advertising.

Answer:

Area = Pi * (r)^2

or, A = πr^2

thus, A = 3.14159 (7)^2

which is A = 3.14159 * 49

which is 150, using appropriate significant figures (I rounded 153.97 down).

Thus, the farmer will need 150Kg.

According the question,:-

Radius of the flower bed = 7 m.

∴ Area of the flower bed will be =  π r2  

                                                       = [tex]\frac{22}{7}[/tex] × (7m)²

                                                     =154m²

Hence total area of the flower bed will be 154m².

If 1 kg of fertilizer is required for 1 square meter area.

then the farmer will need 154kg of fertilizer.

cost of 1 kg of fertilizer =Rs 10

∴ cost of 154 kg will be = 154 ×Rs10 = Rs1540.

Ans :-  Total area of the flower bed will be 154m². And the farmer will need 154kg of fertilizer, which costs Rs1540.

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