The value of the expression 2(4m+7)+3 when m=3 is (a) 41 (b) 44 (c) 56 (d) 43​

Answer:

SEE THIS ATTACHMENT AND PLZ MARK ME AS BRAINLIEST I REQUEST YOU..PLEASE

Step-by-step explanation:

difference = P × ( r/100)^2

150 = P × (4/100)^2

P *= 150 × 625

= 93,750

We first find the simple interest and compound interest assuming the principal to be Rs. x. Then, find the difference between S.I. and C.I. Taking this difference for Rs. x we can find the principal.

Let the principal P=Rs. x,R=4% and N=2 years.

Simple interest,

I=

100

P×N×R

=

100

x×2×4

=Rs.

100

8x

Now compound interest is

A=P(1+

100

R

)

n

=x(1+

100

4

)

2

=x(1.04)

2

=(1.0816)x Rs.

Hence the compound interest =1.0816x−x=0.0816x.

Now, C.I. - S.I. =0.0816x−

100

8x

=

100

8.16x−8x

=

100

0.16x

The difference in CI and SI is Rs. 0.16 when the principal is Rs. x.

But the difference is Rs. 36 then the principal is x=

0.16

100

×36=22,500. Thus the principal is Rs. 22,500

import java .util.*;

class lucky

{

public static void main (String args [ ] )

{

Scanner sc = new Scanner (System. in) ;

int n ;

int sq =0 ;

int d = 0 ;

int s = 0;

System. out.println ("ENTER A NUMBER ")

n = sc. next Int ( );

for ( int i = 1, i < n , i++)

{

d = n modules 10 ;

n = n /10;

sq = d * d ;

s = s+ sq ;

if ( s modules i = = 0)

{

System. out.println ( " LUCKYYYYY NUMBER!! " )

}

else

{

System. out.println ( " NOT SO LUCKY " )

}

}

}

}

• int n - for entering number
• int sq - for calculation of square
• int d - for taking out digit
• int s - for calculating sum
• int i - loop variable

SORRY MY PHONE DOES NOT HAS MODULES OPERATOR THAT'S WHY I'VE WRITTEN "modules "

Answer:

import java.util.*;

public class LuckyNumber

{

public static void main(String args[])

{

Scanner sc = new Scanner (System. in) ;

 int number ;

 int sq =0 , rem = 0,s = 0,rev = 0,count =0;

 System.out.println("ENTER A NUMBER ");

 number = sc. nextInt( );

  while(number != 0 )

  {

   rem = number % 10;

   rev = rev * 10 + rem;

   number /=10;

      count = count +1;

 } // while close

 for(int i = 1;i < count; i++)

 {

 rem = rev % 10 ;

 rev = rev /10;

               if(i%2 ==0) {

 sq = rem * rem ;

 s = s+ sq ;

               }  //if close

 }  // for close

 if ( s%9 == 0 )

 {

 System.out.println( " LUCKYYYYY NUMBER!! " );

 }//if close

 else

 {

              System.out.println( " NOT SO LUCKY " );

 }  //else close

               }//main close

               }// class close

OUTPUT :

ENTER A NUMBER

134359

LUCKYYYYY NUMBER!!

---------------------------------------

ENTER A NUMBER

12212

NOT SO LUCKY

Explanation:

Answer:

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Explanation:

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