Answer:
5 amps
Explanation:
First from the positive terminal of the battery current is going into two branches in 1Ω which are in series. The equivalent Resistance of 1st branch is 2Ω and 2nd branch is also 2Ω. These two connected in parallel give 1Ω which is in series with 1Ω giving the Equivalent resistance of entire circuit as 2Ω.
Thus, R = 2Ω
I = 10/2 = 5 amps
Thus the current is 5 amps flowed by battery