If a rectangular sheet having dimensions 22 cm x 11 cm is rolled along its shorter side to form a cylinder. then the curved surface area of the cylinder so formed is:
Answers 2
Step-by-step explanation:
If a rectangular sheet is rolled along its breadth than the dimensions will be 22cm as height and 11cm as circumference of the circle of the cylinder.
Circumference of circle= 2πr
11cm = 2*22/7*radius
radius = 7/4cm
So, height is 22cm and radius is 7/4cm.
Curved surface area of a cylinder= 2πrh
= 2*22/7*7/4*22
= 242[tex]cm^{2}[/tex]
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Author:
beatricearroyo
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Given,
Dimensions of a rectangular sheet = 22 cm × 11 cm.
It is rolled along the shorter side to form a cylinder.
To find,
The curved surface area of the cylinder formed.
Solution,
This problem can be simply solved by following the below process.
It can be seen that when a rectangular sheet is rolled to form a cylinder, a hollow cylinder will be obtained and the curved surface area of this cylinder will be equal to that of the original rectangular sheet.
So, mathematically,
The curved surface area of the cylinder = the area of the rectangle
⇒ [tex](CSA)_{cyl}=A_{rect}[/tex]
Here, [tex]A_{rect}[/tex] can be determined as,
[tex]A_{rect}=22\times 11[/tex] cm²
⇒ [tex]A_{rect}=242[/tex] cm²
Since both areas will be the same. So,
[tex](CSA)_{cyl}=242 \hspace{3} cm^{2}[/tex].
Therefore, the curved surface area of the cylinder formed will be 242 cm².
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Author:
barbie2z0d
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