Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and p,q respectively (see the figure).prove that angle ACP =angle QCD.prove that a cyclic parallelogram is a rectangle​

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  • matematika

    Subject:

    Math
  • Author:

    robert
  • Created:

    1 year ago

Answers 1

Answer:

⇒Chords AP and DQ are joined.

⇒For chord AP,

⇒∠PBA=∠ACP        ...Angles in the same segment --- (i)

⇒For chord DQ,

⇒∠DBQ=∠QCD        ...Angles in same segment --- (ii)

⇒ABD and PBQ are line segments intersecting at B.

⇒∠PBA=∠DBQ        ...Vertically opposite angles --- (iii)

By the equations (i), (ii) and (iii),

∠ACP=∠QCD

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