mohan took 4 small spherical balls of silver of surface area 887.04 cm^2 each from a blacksmith he wanted them to be made into cylindrical coins of radius one fourth of that of the silver ball and height 4 cm find the radius of the spherical ball

Answers 2

Step-by-step explanation:

Given mohan took 4 small spherical balls of silver of surface area 887.04 cm^2 each from a blacksmith he wanted them to be made into cylindrical coins of radius one fourth of that of the silver ball and height 4 cm

Find the radius of the spherical ball. Also find the curved surface area of the coin.

  • So we have spherical balls of silver of surface area 887.04 cm^2
  • So Surface area of spherical ball is 4πr^2
  •          So 4πr^2 = 887.04
  •                   r^2 = 887.04 / 4π
  •                   r^2 = 887.04 / 12.56
  •                   r^2 = 70.624
  •             Or  r = 8.403
  • According to the question,
  •         Radius of a cylinder coin = ¼ x 8.403
  •                                                   = 2.1 cm
  • Given height of the cylindrical coin is 4 cm
  • Therefore curved surface area of the coin is 2πrh
  •                                                                          = 2 x 22/7 x 2.1 x 4
  •                                                                          = 52.8 sq cm

Reference link will be

https://brainly.in/question/79412

Answer:

Radius of the Spherical ball = 8.4 cm

Radius of cylindrical coin = 2.1 cm

Explanation -

Given, 4 spherical balls of SA 887.04 Each

SA of Spherical ball = 887.04

4πr²=887.04

4×22/7×r² = 887.04 (Taking π as 22/7)

r² = ( 887.04×7) / (22×4)

r² = 70.56

r = √70.56 = 8.4

Therefore , radius of each spherical ball is 8.4cm.

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